How much water would form if 4.8 grams of hydrogen reacted with 38.4 grams of oxygen?

Hydrogen reacts with oxygen to form water based on the following equation:

2H2 + O2 ... > 2H2O

This means that 4 grams of hydrogen are required to react with 32 grams of oxygen to release 36 grams of water.

We need to calculate how munch oxygen is needed to react with 4.8 grams of hydrogen. We can do this using cross multiplication as follows:

amount of oxygen = (4.8x32) / 4 = 38.4 grams

This means that we have no limiting reagent here and both reactants will completely react.

We know that 4 grams of hydrogen are required to produce 36 grams of water. Therefore:

amount of water produced from 4.8 grams of hydrogen = (4.8 x 36) / 4 = 43.2 grams