Ask Question
2 April, 13:57

a chemist reacts 150.0 grams of HCl with an excess of MnO2. if the following reaction occurs: MnO2+4HCl=MnCl2+2H2O+Cl2 how many grams of mncl2 are formed

+1
Answers (2)
  1. 2 April, 14:16
    0
    There are 129.4 grams of MnCl2 formed

    Explanation:

    Step 1: Data given

    Mass of HCl = 150.0 grams

    MnO2 = excess

    Molar mass of HCl = 36.46 g/mol

    Step 2: The balanced equation

    MnO2+4HCl → MnCl2+2H2O+Cl2

    Step 3: Calculate moles of HCl

    Moles HCl = Mass HCl / molar mass HCl

    Moles HCl = 150.0 grams / 36.46 g/mol

    Moles HCl = 4.114 moles

    Step 4: Calculate Moles of MnCl2

    For 1 mol of MnO2 we need 4 moles of HCl to produce 1 mol of MnCl2, 2 moles of H2O and 1 mol Cl2

    For 4.114 moles of HCl we'll have 4.114/4 = 1.0285 moles of MnCl2

    Step 5: Calculate mass of MnCl2

    Mass MnCl2 = moles MnCl2 * molar mass MnCl2

    Mass MnCl2 = 1.0285 * 125.84 g/mol

    Mass MnCl2 = 129.4 grams

    There are 129.4 grams of MnCl2 formed
  2. 2 April, 14:20
    0
    There are formed 98.05 g of MnCl₂

    Explanation:

    The reaction is this one:

    MnO₂ + 4 HCl → MnCl₂ + 2 H₂O + Cl₂

    First of all, determinate moles. Divide mass / molar mass

    150 g / 36.45 g/m = 4.11 moles of HCl

    Ratio between HCl and MnCl₂ is 4:1

    4 moles of HCl produce 1 mol of Chloride

    4.11 moles of HCl 'll produce (4.11. 1) / 4 = 1.03 moles of chloride

    Molar mass. Moles = Mass

    Molar Mass MnCl₂ = 95.2 g/m

    95.2 g/m. 1.03 moles = 98.05 grams
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “a chemist reacts 150.0 grams of HCl with an excess of MnO2. if the following reaction occurs: MnO2+4HCl=MnCl2+2H2O+Cl2 how many grams of ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers