Calculate how many moles of no2 form when each quantity of reactant completely reacts. 2n2o5 (

g.→4no2 (

g.+o2 (

g.

2 moles of N2O5 = 4 moles of NO2

2.4 mol N2O5/1 X 4 mol NO2/2 mol N2O5 (this way you can cross out the N2O5 mol and just be left with NO2 mol)

2.4 X 4 = 9.6

9.6/2 = 4.8

4.8 mol NO2 are formed