If 0.582 moles of zinc reacts with excess lead (IV) sulfate how many grams are zinc sulfate would be produced?

Question

Zayden Choi

Chemistry

30 July, 02:42

If 0.582 moles of zinc reacts with excess lead (IV) sulfate how many grams are zinc sulfate would be produced?

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Mccarthy · Answer 1

From the balanced equation 2 moles of Zn make 2 moles of ZnSO4

You have 0.582 moles of zinc so you make 0.582 moles of ZnSO4.

Calculate the molar mass of ZnSO4. Multiply that by the moles of ZnSO4.

molar mass of ZnSO4 = 161.47 g/mol

zinc sulfate produced = 161.47 g/mol x 0.582 moles

= 93.97 grams