Ammonia reacts with oxygen according to the equation: 4 nh3 (g) + 5 o2 (g) → 4 no (g) + 6 h2o (g) δhrxn = - 906 kj calculate the heat (in kj) associated with the complete reaction of 155 g of nh3.

Question

Brianna Acosta

Chemistry

28 June, 12:39

Ammonia reacts with oxygen according to the equation: 4 nh3 (g) + 5 o2 (g) → 4 no (g) + 6 h2o (g) δhrxn = - 906 kj calculate the heat (in kj) associated with the complete reaction of 155 g of nh3.

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Toodles · Answer 1

First, we need to get the number of moles of NH3:

no. of moles = mass of NH3 / molar mass

when we have the mass = 155g & the molar mass of NH3 = 14 + (1x3) = 17 g/mol

∴ no. of moles = 155g/17mol/g

= 9.12 moles

∴ the heat (in Kj) = no. of moles of NH3 * (ΔHrxn/4moles NH3)

= 9.12 moles * (-906 / 4mol NH3)

= - 2065.68 KJ