Given a gas inside a 2.93 L container at a temperature of 20 Celsius. The temp increases to

40 Celsius. what happens to the volume of gas and whose gas law is this?

Question

Jenna Wells

Chemistry

24 November, 13:02

Given a gas inside a 2.93 L container at a temperature of 20 Celsius. The temp increases to

40 Celsius. what happens to the volume of gas and whose gas law is this?

+1

Answers (1)

Know the Answer?

Corinne Melendez · Answer 1

New Gas volume (V2) = 5.86 L

Explanation:

Given:

Gas volume (V1) = 2.93 L

Temperature (T1) = 20°Celsius

After Increasing temperature:

New Temperature (T2) = 40°Celsius

Find:

New Gas volume (V2) = ?

Computation:

According to Charles' gas Law:

⇒ Gas volume (V1) / Temperature (T1) = New Gas volume (V2) / New Temperature (T2)

⇒ 2.93 L / 20°Celsius = New Gas volume (V2) / 40°Celsius

⇒ New Gas volume (V2) = 5.86 L

Given a gas inside a 2.93 L container at a temperature of 20 Celsius. The temp increases to40 Celsius. what happens to the volume of gas and whose gas law is this?

Given a gas inside a 2.93 L container at a temperature of 20 Celsius. The temp increases to

40 Celsius. what happens to the volume of gas and whose gas law is this?