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15 February, 00:18

A container of oxygen gas is at standard temperature and pressure (STP; 1 atm of pressure and 0°C).

If this sample is put into an oven at 280°C, what would its pressure be, in atmospheres? (Volume is

constant)

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Answers (1)
  1. 15 February, 00:27
    0
    2.03atm

    Explanation:

    Step 1:

    Data obtained from the question. This include the following:

    Initial pressure (P1) = 1atm

    Initial temperature (T1) = 0°C = 0°C + 273 = 273K

    Final temperature (T2) = 280°C = 280°C + 273 = 553K

    Final pressure (P2) = ... ?

    Step 2:

    Determination of the new pressure of the gas.

    Since the volume of the gas is constant, the following equation:

    P1/T1 = P2/T2

    will be used to obtain the pressure. This is illustrated below:

    P1/T1 = P2/T2

    1/273 = P2 / 553

    Cross multiply

    273x P2 = 553

    Divide both side by 273

    P2 = 553/273

    P2 = 2.03atm

    Therefore, the new pressure of the gas will be 2.03atm
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