1 - A gas occupies a volume of 4.0 L at 2.5 kPa. What volume will the gas occupy at 20.0 kPa?

I

Answer: 0.5L

Explanation:

Using Boyle's law

P1V1=P2V2

P1 = 2.5kpa

V1 = 4l

V2=?

P2 = 20.0kpa

Substitute the value into this formula

P1V1=P2V2

2.5*4=20*V2

Cross multiply

2.5*4=20V2

V2 = 2.5*4/20

V2 = 80/2.5

V2 = 0.5L

So 0.5L of gas will occupy 20.0kpa

0.5 L

Explanation:

V1 (initial volume) = 4 L

P1 (initial pressure) = 2.5 kPa

P2 (final pressure) = 20 kPa

V2 (final volume) = ?

Use Boyle's law P1V1 = P2V2, to find the the final volume

P1V1 = P2V2

2.5 x 4 = 20 x V2

Divide both side by 20

V2 = (2.5 x 4) / 20

V2 = 0.5 L