Molecular bromine is 24 percent dissociated at 1600 k and 1.00 bar in the equilibrium br2 (

g. = 2br (

g. calculate kp at 1600 k.

Br2 = = 2Br

24% dissociated = > n total moles, 0.24 mol*n of Br, and 0.76*n mol of Br2

=> partial pressure of Br, P Br = 0.24 bar, and

partical pressure of Br2, P Br2 = 0.76 bar

kp = (P Br) ^2 / P Br2 = (0.24) ^2 / 0.76 = 0.0758