The following reaction shows sodium hydroxide reacting with sulfuric acid.

4NaOH + 2H2SO4 → 2Na2SO4 + 4H2O

How many grams of Na2SO4 are produced from 10.0 grams of NaOH?

(Molar mass of Na = 22.989 g/mol, O = 15.999 g/mol, H = 1.008 g/mol, S = 32.065 g/mol)

17.8 grams

19.2 grams

35.5 grams

38.5 grams

Question

Arjun

Chemistry

10 February, 07:37

The following reaction shows sodium hydroxide reacting with sulfuric acid.

4NaOH + 2H2SO4 → 2Na2SO4 + 4H2O

How many grams of Na2SO4 are produced from 10.0 grams of NaOH?

(Molar mass of Na = 22.989 g/mol, O = 15.999 g/mol, H = 1.008 g/mol, S = 32.065 g/mol)

17.8 grams

19.2 grams

35.5 grams

38.5 grams

+1

Answers (1)

Know the Answer?

Evan · Answer 1

Answer: 17.8grams

Explanation:

Equate the number of moles of NaOH to the number of moles of Na2SO4

No of mole = reacting mass / molar mass

10/40 x 4 = mass of Na2SO4/142 x 2

10/160 = x/284

X = 284 x 10/160

X = 17.8 grams

The following reaction shows sodium hydroxide reacting with sulfuric acid.4NaOH + 2H2SO4 → 2Na2SO4 + 4H2OHow many grams of Na2SO4 are produced from 10.0 grams of NaOH?(Molar mass of Na = 22.989 g/mol, O = 15.999 g/mol, H = 1.008 g/mol, S = 32.065 g/mol)17.8 grams19.2 grams35.5 grams38.5 grams