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5 April, 15:24

Over an interval of 3.00 s the average rate of change of the concentration of C was measured to be 0.0840 M/s. What is the final concentration of D at the end of this same interval if its concentration was initially 3.000 M?

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  1. 5 April, 15:47
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    Final Concentration = 3.252M

    Explanation:

    Let's bring out the data mentioned in the question.

    Time, t = 3s

    Rate = 0.0840 M/s

    Initial Concentration = 3M

    Final Concentration = x

    The formular relating these parameters is;

    Rate = ΔConcentration / ΔTime

    Upon solving for ΔConcentration, we have;

    ΔConcentration = Rate * ΔTime

    ΔConcentration = 0.0840 * 3

    ΔConcentration = 0.252

    But ΔConcentration = Final Concentration - Initial Concentration

    Hence,

    Final Concentration = ΔConcentration + Initial Concentration

    Final Concentration = 0.252 + 3

    Final Concentration = 3.252M
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