If I have 340 mL of a 0.5 M NaBr solution, what will the concentration be if I add

400 mL more water to it?

A. 0.03 molar

B. 0.13 molar

C. 0.23 molar

D. 0.33 molar

Option C. 0.23 molar

Explanation:

The following data were obtained from the question given:

C1 = 0.5 M

V1 = 340mL

V2 = since 400mL was added to the original volume, therefore = 340 + 400 = 740mL

C2 = ?

The concentration of the diluted solution can be calculated by using the following:

C1V1 = C2V2

0.5 x 340 = C2 x 740

Divide both side by 740

C2 = (0.5 x 340) / 740

C2 = 0.23M

Therefore, the new concentration of the solution is 0.23M