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6 March, 17:24

A gas that exerts a pressure of 2.15 atm in a container with a volume of 0.0900 L will exert a pressure of ___ atm when transferred to a container with a volume of a 4.75 L

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  1. 6 March, 17:51
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    Given:

    Initial pressure exerted by the gas P1 = 2.15 atm

    Initial volume of the container V1 = 0.0900 L

    Final volume of the new container V2 = 4.75 L

    To determine:

    Pressure P2 exerted by the gas in the new container

    Explanation:

    The ideal gas equation is given as-

    PV = nRT

    where n = moles of the gas

    R = gas constant and T = temperature

    Since the values of n, R, T do not change when the gas is transferred to the new container, we have the relation

    PV = constant

    or, P1V1 = P2V2

    P2 = P1V1/V2 = 2.15 * 0.0900/4.75 = 0.041 atm

    Ans: The pressure exerted by the gas in the new container is 0.041 atm
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