What is the new pressure on a 3.5 liter ballon if its orginal volume was 5.8 l at 2.7 atm of pressure?

Question

Beau Mendez

Chemistry

8 June, 06:56

What is the new pressure on a 3.5 liter ballon if its orginal volume was 5.8 l at 2.7 atm of pressure?

+4

Answers (2)

Know the Answer?

Kymani Carrillo · Answer 1

Answer: P = 4.5 atm

Explanation: For this problem we will use Boyle's Law to solve for the new pressure. Boyle's Law is expressed in the formula P1V1=P2V2. Derive to find P2.

P2 = P1V1/V2

= 2.7 atm (5.8 L) / 3.5 L

= 4.5 atm

Alvaro Kent · Answer 2

4.47 atm

Explanation:

Pressure and volume are inversely related, when one goes up the other goes down. In this case the volume went down so it would make sense that the pressure increases. The equation to this is P (1) times v (1) = p (2) times V (2). So when solving you would have (5.8) (2.7) = (3.5) (?). When solving you get 15.66 = (3.5) (?), then divide by 3.5 on both sides. Thus your answer.