How many atoms of phosphorus are in 2.30 mol of copper (II) phosphate? I'm having trouble figuring out the steps. I do know Avogadro's number is needed! 6.022x10^23

Question

Lorelei

Chemistry

18 November, 19:47

How many atoms of phosphorus are in 2.30 mol of copper (II) phosphate? I'm having trouble figuring out the steps. I do know Avogadro's number is needed! 6.022x10^23

+1

Answers (1)

Know the Answer?

Larson · Answer 1

Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. The calculation is as follows:

2.30 mol Cu3 (PO4) 2 (2 mol P / 1 mol Cu3 (PO4) 2) (6.022 x 10^23 atoms / mole) = 2.77 x 10^24 atoms P