Ask Question
29 December, 21:51

A sample of ethanol has a mass of 36.7 g.

a) How many carbon atoms does the sample contain?

b) How many hydrogen atoms are present?

c) How many oxygen atoms are present?

+1
Answers (2)
  1. 29 December, 22:00
    0
    C atoms = 9.6 * 10^23 atoms

    H atoms = 2.9*10^24 atoms

    O atoms = 4.8 * 10^23 atoms

    Explanation:

    Step 1: Data given

    Mass of ethanol = 36.7 grams

    Molar mass of ethanol = 46.07 g/mol

    Step 2: Calculate moles of ethanol

    Moles ethanol = mass / molar mass

    Moles ethanol = 36.7 grams / 46.07 g/mol

    Moles ethanol = 0.797 moles

    Step 3: Calculate moles

    For 1 mol C2H5OH we have 2 moles C, 6 moles H and 1 mol O

    For 0.797 moles C2H5OH we have:

    2*0.797 = 1.594 moles C

    6*0.797 = 4.782 moles H

    1*0.797 = 0.797 moles O

    Step 4: Calculate carbon atoms

    C atoms = moles C * number of Avogadro

    C atoms = 1.594 moles * 6.02 * 10^23

    C atoms = 9.6 * 10^23 atoms

    Step 5: Calculate H atoms

    H atoms = 4.782 moles * 6.02 * 10^23

    H atoms = 2.9*10^24 atoms

    Step 6: Calculate O atoms

    O atoms = 0.797 moles * 6.02 * 10^23

    O atoms = 4.8 * 10^23 atoms
  2. 29 December, 22:15
    0
    Below in bold.

    Explanation:

    1 mole of an element contains 6.022 * 10^23 atoms.

    Ethanol has the molecular formula C2H5OH.

    So we have 2 carbon atoms, 6 hydrogen atoms ans 1 oxygen atom in the molecule.

    Using molar masses the mass of carbon in 36.7 g of C2H5OH

    = [ (2 * 12.011) / (2*12.011 + 6*1.008 + 15.999) ] * 36.7

    = [ (2 * 12.011) / 46.069] * 36.7

    = 19.14 g

    So the number of carbon atoms = (19.14 / 12.011) * 6.022 * 10^23

    = 9.596 * 10^23. (Answer).

    Using molar masses the mass of hydrogen in 36.7 g of C2H5OH

    = [ (6 * 1.008) / (46.069) ] * 36.7

    = 4.818 g

    So the number of hydrogen atoms = (4.818 / 1.008) * 6.022 * 10^23

    = 2.878 * 10^24 (Answer).

    Using molar masses the mass of oxygen in 36.7 g of C2H5OH

    = [ (15.999) / (46.069) ] * 36.7

    = 12.745 g

    So the number of hydrogen atoms = (12.745 / 15.999) * 6.022 * 10^23

    = 2.924 * 10^24 (Answer).
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A sample of ethanol has a mass of 36.7 g. a) How many carbon atoms does the sample contain? b) How many hydrogen atoms are present? c) How ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers