What mass of NaOH is in 3.0e+02 mL of a 5.0 M NaOH solution?

Question

Lane Galvan

Chemistry

5 August, 09:37

What mass of NaOH is in 3.0e+02 mL of a 5.0 M NaOH solution?

+2

Answers (1)

Know the Answer?

Aubrey · Answer 1

Answer is: mass of sodium hydroxide is 60 grams.

V (NaOH) = 300 mL · 1 L/1000mL = 0,3 L.

c (NaOH) = 5 M = 5 mol/L.

n (NaOH) = c (NaOH) · V (NaOH).

n (NaOH) = 5 mol/L · 0,3 L.

n (NaOH) = 1,5 mol.

m (NaOH) = n (NaOH) · M (NaOH).

m (NaOH) = 1,5 mol · 40 g/mol.

m (NaOH) = 60 g.