The four following concentrated solutions are each diluted with water to form 200 mL of a dilute solution. Which solution, once diluted to 200 mL, will have the largest concentration? View Available Hint (s) The four following concentrated solutions are each diluted with water to form 200 mL of a dilute solution. Which solution, once diluted to 200 mL, will have the largest concentration? 100.0 mL of a 0.1 M NaOH solution 20.0 mL of a 0.4 M NaOH solution 80.0 mL of a 0.2 M NaOH solution. 10.0 mL of a 0.5 M NaOH solution

80.0 mL of a 0.2 M NaOH solution.

Explanation:

To solve this problem, we must mention that the no. of millimoles of the substance is equal before and after dilution.

(MV) before dilution = (MV) after dilution.

We need to calculate the concentration after the dilution for each solution:

100.0 mL of a 0.1 M NaOH solution:

M after dilution = (MV) before dilution/V after dilution = (0.1 M) (100.0 mL) / (200.0 mL) = 0.05 M.

20.0 mL of a 0.4 M NaOH solution:

M after dilution = (MV) before dilution/V after dilution = (0.4 M) (20.0 mL) / (200.0 mL) = 0.04 M.

80.0 mL of a 0.2 M NaOH solution:

M after dilution = (MV) before dilution/V after dilution = (0.2 M) (80.0 mL) / (200.0 mL) = 0.08 M.

10.0 mL of a 0.5 M NaOH solution:

M after dilution = (MV) before dilution/V after dilution = (0.5 M) (10.0 mL) / (200.0 mL) = 0.025 M.

So, 80.0 mL of a 0.2 M NaOH solution will have the largest concentration after dilution to 200.0 mL.