What was the initial pressure of a gas that had an initial temperature of 905 k and an initial volume of 14.3 l, with a final pressure of 0.83 atm, a final temperature of 154 k and a final volume of 2.7 l? (a) 26 atm (b) 0.27 atm (c) 0.75 atm (d) 1.3 atm (e) 0.92 atm?

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17 June, 02:05

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Aliana Trevino · Answer 1

1. P1V1/T1=P2V2/T2

2. (p1) (14.3) / 905K = (.83) (2.7) / 154K

3. (p1) (14.3) / 905K=.0146

4 ...0146*905K/14.3=.92 atm

answer is e,.92 atm