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27 August, 00:04

How many grams of zns are required to react with 12.6 l of oxygen gas at stp?

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  1. 27 August, 00:56
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    The balanced chemical equation:

    2 ZnS + 3 O₂ → 2 ZnO + 2 SO₂

    1 mole of any gas at STP occupies 22.4 L

    ? mole of O₂ gas at STP will occupy 12.6 L

    we have 0.5625 mole of O₂

    From the balanced equation we see that:

    2 moles of ZnS react with 3 moles O₂

    ? mole ZnS react with 0.5625 mole O₂

    Number of moles of ZnS = 0.375 mol

    mass of ZnS = 0.375 * 97.45 (Molar mass) = 36.5 g ZnS
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