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8 July, 17:27

In each cycle of a Carnot engine, 104 J of heat is absorbed from the high-temperature reservoir and 51 J is exhausted to the lowtemperature reservoir. What is the efficiency of the engine?

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  1. 8 July, 17:47
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    the efficiency of the Carnot engine is e=0.5060 (50.96%)

    Explanation:

    The carnot cycle effifiency e is calculated through

    e = W/Q₂

    where

    W = work

    Q₂ = heat absorbed

    Q₁ = heat exhausted

    from an energy balance

    W = Q₂ - Q₁ (the proportion of the heat absorbed that was not released was converted to work)

    therefore

    e = (Q₂-Q₁) / Q₂ = 1 - Q₁/Q₂ = 1 - 51 J/104 J = 0.5060 (50.96%)
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