What mass of Al2O3 (alumina, a finely divided white powder that is produced as billows of white smoke) is formed in the reaction of 2800 kg of aluminum?

5290.7 kg of Al₂O₃ are produced in the reaction of 2800 kg of Al

Explanation:

The reaction to produce alumina is:

4 Al + 3O₂ → 2 Al₂O₃

So, let's convert the mass of Al to moles (mass / molar mass)

2800 kg = 2800000 g (Then, 2.8 * 10⁶ g)

2.8 * 10⁶ g / 26.98 g/mol = 103780.5 moles of Al

Ratio is 4:2, so with the moles I have, I will produce the half of moles of alumina.

103780.5 mol / 2 = 51890.25 moles of Al₂O₃

Now we can convert these moles to mass (molar mass. mol)

101.96 g/mol. 51890.25 mol = 5290729.8 g

5290729.8 g → 5290.7 kg