A container of gas is at a pressure of 1.3x10^5 Pa and a volume of 6 m^3. How much work is done by the gas if it expands at a constant pressure to twice its initial volume.

Question

Essence Gibbs

Chemistry

17 January, 18:57

A container of gas is at a pressure of 1.3x10^5 Pa and a volume of 6 m^3. How much work is done by the gas if it expands at a constant pressure to twice its initial volume.

+2

Answers (1)

Know the Answer?

Santino Barnes · Answer 1

In thermodynamics, work of a system at constant pressure conditions is equal to the product of the pressure and the change in volume. It is expressed as follows:

W = P (V2 - V1)

W = 1.3x10^5 (2x6 - 6)

W = 780000 J

Hope this answers the question. Have a nice day.