Ask Question
3 October, 02:54

A 5.00 g mixture of methane (CH4) and ethane (C2H6) is combusted in oxygen gas to produce carbon dioxide and water. If 14.09 g of CO2 is produced, how many grams of methane was in the original 5.00 g mixture?

+1
Answers (1)
  1. 3 October, 03:16
    0
    We have two unknowns for this problem. These are the amount of Ch4 and the amount of C2H6. We let these as x and y respectively. It should be that we generate two equation in order to solve this problem. We do as follows:

    Equation 1:

    x + y = 5

    Equation 2

    CO2 produced from CH4 + CO2 produced from C2H6 = 14.09

    x (44.01/16.05) + y (4) (44.01) / (2) (30.08) = 14.09

    2.74x + 2.93y = 14.09

    Solving simultaneously,

    x = 2.95 g CH4

    y = 2.05 g C2H6
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A 5.00 g mixture of methane (CH4) and ethane (C2H6) is combusted in oxygen gas to produce carbon dioxide and water. If 14.09 g of CO2 is ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers