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Today, 07:18

using the equaation 2h2+o2-->2h2o if 10.0g of hydrogen are used in the presence of excess oxygen how many grams of water will e produced

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  1. Today, 07:38
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    90g of H2O

    Explanation:

    2H2 + O2 - > 2H2O

    First, we calculate the molar masses of H2 And H20.

    Molar Mass of H2 = 2g/mol

    Mass conc of H2 from the balanced equation = 2 x 2 = 4g

    Molar Mass of H2O = 2 + 16 = 18g/mol

    Mass conc of H2O from the balanced equation = 2x18 = 36g

    From the equation,

    4g of H2 produced 36g of H2O

    Therefore, 10g of H2 will be produce = (10x36) / 4 = 90g of H2O
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