In the first step of glycolysis, the given two reactions are coupled. reaction 1: glucose + P i ⟶ glucose - 6 - phosphate + H 2 O Δ G = + 13.8 k J / mol reaction 2: ATP + H 2 O ⟶ ADP + P i Δ G = - 30.5 k J / mol Answer the four questions about the first step of glycolysis. Is reaction 2 spontaneous or nonspontaneous? nonspontaneous spontaneous Complete the net chemical equation. ATP + ⟶ + Calculate the overall ΔG for the coupled reaction. Δ G = kJ / mol Is the first step in glycolysis spontaneous (favorable) ? no yes

Question

Konner Simmons

Chemistry

10 October, 23:17

In the first step of glycolysis, the given two reactions are coupled. reaction 1: glucose + P i ⟶ glucose - 6 - phosphate + H 2 O Δ G = + 13.8 k J / mol reaction 2: ATP + H 2 O ⟶ ADP + P i Δ G = - 30.5 k J / mol Answer the four questions about the first step of glycolysis. Is reaction 2 spontaneous or nonspontaneous? nonspontaneous spontaneous Complete the net chemical equation. ATP + ⟶ + Calculate the overall ΔG for the coupled reaction. Δ G = kJ / mol Is the first step in glycolysis spontaneous (favorable) ? no yes

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Jaxson Hodge · Answer 1

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Explanation:

Glycolysis is the process in the field of chemistry in which a specific glucose molecule is broken down to become two or more molecules of pyruvic acid or pyruvate. The process and procedure is a metabolic multi-step pathway that happens in the cytoplasm of plant cells, animal cells, and the cells of various microorganisms.

The answer to the question above is:

1) nonspontaneous because deltaG is positive

2) glucose + ATP - -> glucose-6-phosphate + ADP

3) - 16.7 kJ/mol

4) yes, because deltaG is negative