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5 November, 21:23

35mL of acid with an unknown concentration is titrated to completion using 63mL of 3.0 MNaOH.

What is the concentration of the acid?

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  1. 5 November, 21:38
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    5.4 M.

    Explanation:

    At complete neutralization: It is known that the no. of millimoles of acid equal that of the base.

    (MV) acid = (MV) NaOH

    M of acid = ? M, V of acid = 35.0 mL.

    M of NaOH = 3.0 M, V of NaOH = 63.0 mL.

    ∴ M of acid = (MV) NaOH / (V) acid = (3.0 M) (63.0 mL) / (35.0 mL) = 5.4 M.
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