Calculate the volume that 12.5 g of Co, gas will occupy at a

temperature of 40°C and a pressure of 1.20 atm.

M = 12.5 g

T = 40 C = 313 K

P = 1.20 atm

R = 0.0821 L. atm/mol. K (constant)

V = ?

Using equation

PV = nRT

Find the number of moles which is

n = m/Mr

Mr (find it in the periodic table)

So, then apply the values

V = nRT / P

and you will got the volume

Actually I didn't solve it, because I didn't understand the substance, is it Co (Cobalt) or CO (carbon monoxide) ?

If it Co, so the number of moles will be

n = 12.5 g / 59 g/mol

:. n = 0.212 g/mol

So the volume is

V = (0.212 g/mol x 0.0821 L. atm/mol. K x 313 K) / 1.20 atm

:. V = 4.54 L