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11 April, 11:26

At a temperature of 280 K, the gas in a cylinder has a volume of 20.0 liters. If the volume of the gas is decreased to 10.0 liters, what must the temperature be for the gas pressure to remain constant?

A. 140 K

B. 273 K

C. 560 K

D. 5600 K

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Answers (1)
  1. 11 April, 11:46
    0
    To solve this we assume that the gas inside is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

    T1 / V1 = T2 / V2

    T2 = T1 x V2 / V1

    T2 = 280 x 20.0 / 10

    T2 = 560 K
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