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17 March, 08:30

The recommended daily allowance (rda of calcium is 1.2 g. calcium carbonate contains 12.0% calcium by mass. how many grams of calcium carbonate are needed to provide the rda of calcium?

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  1. 17 March, 08:42
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    1) Calcium carbonate contains 40.0% calcium by weight.

    M (CaCO₃) = 100.1 g/mol

    M (Ca) = 40.1 g/mol

    w (Ca) = 40.1/100.1=0.400 (40.0%) !

    2) Mass fraction of this is excessive data.

    3) The solution is:

    m (Ca) = 1.2 g

    m (CaCO₃) = M (CaCO₃) * m (Ca) / M (Ca)

    m (CaCO₃) = 100.1g/mol*1.2g/40.1g/mol=3.0 g
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