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13 May, 15:37

The decomposition of hi has a rate constant of 1.80 * 10-3 m-1s-1. how much hi remains after 8.50 min if the initial concentration of hi is 4.78 m?

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  1. 13 May, 15:43
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    By use second order integrated integrated law

    1 / (A) t = Kt + 1 / (A) o

    k = constant

    t = time in second = 8.50 x60 = 510 sec

    (A) o = initial concentration

    (A) t = final concentration

    1 / (A) t = (1.80 x10^-3) (510) + 1 / 4.78

    1 (A) t = 1.127 multiply both side by (A) t

    1=1.127 (A) t divide both side by 1.127

    (A) t = 0.887 M
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