Ask Question
14 July, 00:48

2Na (s) + 2H2O (l) → 2NaOH (aq) + H2 (g) When 2 moles of Na react with water at 25°C and 1 atm, the volume of H2 formed is 24.5 L. Calculate the magnitude of work done in joules when 0.45 g of Na reacts with water under the same conditions. (The conversion factor is 1 L · atm = 101.3 J.)

+2
Answers (1)
  1. 14 July, 01:15
    0
    Magnitude of work done = 24.28 J

    Explanation:

    No. of moles = Reacting mass / Molar mass

    Reacting mass of Na = 0.45 g

    Molar mass of sodium = 23g/mol

    ∴ No. of moles of sodium = 0.45/23 = 0.0196 mole

    If 2 moles of Na react with water at 25°C and 1 atm, 24.5 L of H₂ was formed.

    ∴ when 0.0196 mole of Na react with water under the same conditions, (24.5*0.0196) / 2 L of H₂ will be formed.

    ⇒ (24.5*0.0196) / 2 L = 0.24 L

    0.24 L * 1 atm = 0.24 L. atm

    Since 1 L · atm = 101.3 J

    ∴ 0.24 L. atm = (0.24 L. atm * 101.3) / 1 = 24.28 J

    Magnitude of work done = 24.28 J
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “2Na (s) + 2H2O (l) → 2NaOH (aq) + H2 (g) When 2 moles of Na react with water at 25°C and 1 atm, the volume of H2 formed is 24.5 L. ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers