17. If the solubility of a gas is 10.5 g/L at 525 kPa pressure, what is the solubility of the gas when the pressure is 225 kPa? Show your work.

4.5 g/L.

Explanation:

To solve this problem, we must mention Henry's law. Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid. It can be expressed as: P = KS,

P is the partial pressure of the gas above the solution.

K is the Henry's law constant,

S is the solubility of the gas.

At two different pressures, we have two different solubilities of the gas.

∴ P₁S₂ = P₂S₁.

P₁ = 525.0 kPa & S₁ = 10.5 g/L.

P₂ = 225.0 kPa & S₂ = ? g/L.

∴ S₂ = P₂S₁/P₁ = (225.0 kPa) (10.5 g/L) / (525.0 kPa) = 4.5 g/L.