A 50.0 g sample of an unknown metal at 100.0∘C is placed in 500. g of water at 25.00∘C. The final temperature of the system is 27.40∘C. What is the specific heat of the metal in joules per gram degree Celsius?

Question

Kaitlyn Brewer

Chemistry

22 November, 23:27

A 50.0 g sample of an unknown metal at 100.0∘C is placed in 500. g of water at 25.00∘C. The final temperature of the system is 27.40∘C. What is the specific heat of the metal in joules per gram degree Celsius?

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Answers (1)

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Annie · Answer 1

The answer to your question is C = 1.38 J/g°C

Explanation:

Data

Sample Water

mass = ms = 50 g mass = mw = 500 g

T1 = 100°C T1 = 25°C

T2 = 27.4°C T2 = 27.4°C

C = ? C = 4.18 J/g°C

Formula

- Heat release = Heat absorbe

- msC (T2 - T1) = mwC (T2 - T1)

Substitution

-50 (27.4 - 100) C = 500 (4.18) (27.4 - 25)

Simplification

-50 (-72.6) C = 500 (4.18) (2.4)

3630C = 5016

Solve for C

C = 5016 / 3630

Result

C = 1.38 J/g°C