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22 November, 23:27

A 50.0 g sample of an unknown metal at 100.0∘C is placed in 500. g of water at 25.00∘C. The final temperature of the system is 27.40∘C. What is the specific heat of the metal in joules per gram degree Celsius?

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  1. 22 November, 23:46
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    The answer to your question is C = 1.38 J/g°C

    Explanation:

    Data

    Sample Water

    mass = ms = 50 g mass = mw = 500 g

    T1 = 100°C T1 = 25°C

    T2 = 27.4°C T2 = 27.4°C

    C = ? C = 4.18 J/g°C

    Formula

    - Heat release = Heat absorbe

    - msC (T2 - T1) = mwC (T2 - T1)

    Substitution

    -50 (27.4 - 100) C = 500 (4.18) (27.4 - 25)

    Simplification

    -50 (-72.6) C = 500 (4.18) (2.4)

    3630C = 5016

    Solve for C

    C = 5016 / 3630

    Result

    C = 1.38 J/g°C
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