When 8.00x10^22 molecules of ammonia react with 7.00x10^22 molecules of oxygen according to the chemical equation shown below, how many grams of nitrogen gas are produced?

4NH3 (g) + 3O2 (g) - - - >2N2 (g) + 6H2O (g)

NH₃:

N = 8*10²²

NA = 6.02*10²³

n = N/NA = 8*10²²/6.02*10²³ ≈ 1.33*10⁻¹=0.133mol

O₂:

N=7*10²²

NA = 6.02*10²³

n = N/NA = 7*10²²/6.02*10²³ = 1.16*10⁻¹=0.116mol

4NH₃ + 3O ₂ ⇒ 2N ₂ + 6H ₂ O

4mol : 3mol : 2mol

0.133mol : 0.116mol : 0,0665mol

limiting reactant

N₂:

n = 0.0665mol

M = 28g/mol

m = n*M = 0.0665mol*28g/mol = 1,862g