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31 October, 10:31

If 325 g of ammonia is used, what amount, in moles, of nitrogen monoxide will be produced in the

following equation: 4NH3 (g) + 5O2 (g) → 4NO (g) + 6H2O (g) ?

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  1. 31 October, 10:47
    0
    19.12 moles of NO will produced.

    Explanation:

    Given dа ta:

    Mass of ammonia = 325 g

    Moles of NO produced = ?

    Solution:

    Chemical equation:

    4NH₃ + 5O₂ → 4NO + 6H₂O

    Number of moles of Ammonia:

    Number of moles = mass / molar mass

    Number of moles = 325 g / 17 g/mol

    Number of moles = 19.12 mol

    Now we will compare the moles of ammonia and NO.

    NH₃ : NO

    4 : 4

    19.12 : 19.12

    Thus 19.12 moles of NO will produced.
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