Use the following MO diagram for Be2, Be2+, and Be2-. Based on this diagram,

Be2 + is more stable than Be2, and Be2 is more stable than Be2-.

Be2 - is more stable than Be2, and Be2 is more stable than Be2+.

Be2 + and Be2 - are both more stable than Be2.

Be2 is more stable than either Be2 + or Be2-.

Question

Janelle

Chemistry

17 October, 14:38

Use the following MO diagram for Be2, Be2+, and Be2-. Based on this diagram,

Be2 + is more stable than Be2, and Be2 is more stable than Be2-.

Be2 - is more stable than Be2, and Be2 is more stable than Be2+.

Be2 + and Be2 - are both more stable than Be2.

Be2 is more stable than either Be2 + or Be2-.

+2

Answers (1)

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Dangelo Costa · Answer 1

Bond Order = [Σ (bonding e-) - Σ (antibonding e-) ]/2

Be2 = 4e = σ1 (2e) σ2 * (2e) σ3 (0) π1 (0) π2 * (0) σ4 * (0) bo = 0

[Be2] + = 3e = σ1 (2e) σ2 * (1e) σ3 (0) π1 (0) π2 * (0) σ4 * (0) bo = 0.5

[Be2] + would be more likely to exist since it has a bond order of 0.5 whereas Be2 has zero bond order

Use the following MO diagram for Be2, Be2+, and Be2-. Based on this diagram,Be2 + is more stable than Be2, and Be2 is more stable than Be2-.Be2 - is more stable than Be2, and Be2 is more stable than Be2+.Be2 + and Be2 - are both more stable than Be2.Be2 is more stable than either Be2 + or Be2-.