How much water must be added to 36.0 g of srcl2 to produce a solution that is 35.0 wt% srcl2? how much water must be added to 36.0 of to produce a solution that is 35.0 wt%? 48.6 g 66.9 g 103 g 97.2 g?

To solve this problem we will use the following equation:

w = (m of solute) / (m of solution)

w - percentage

It is necessary to mention here that mass of solution is a sum of the mass of solute and mass of water.

w = mass CaCl2 / (mass of water + mass of CaCl2)

mass of water = x

0.35 = 36 / (x + 36)

0.35 * (x + 36) = 36

0.35x + 12.6 = 36

0.35x = 23.4

x = 66.86 g of water is necessary