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13 January, 12:42

Calculate the mass of Cu (NO3) 2.4H2O required to prepare 100.0 mL of 0.200 M solution.

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  1. 13 January, 13:08
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    8921.96g

    Explanation:

    Molar mass of Cu (NO3) 2.4H2O = 446.0982g/mol

    Number of mole = concentrate * volume

    n = 100*0.2=20

    No of mole = mass/molar mass

    Mass = 20*446.0982

    Mass = 8921.96g

    Mass = 8.9kg.
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