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17 July, 04:09

At standard temperature and pressure (0 ∘C∘C and 1.00 atmatm), 1.00 molmol of an ideal gas occupies a volume of 22.4 LL. What volume would the same amount of gas occupy at the same pressure and 35 ∘C∘C?

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  1. 17 July, 04:35
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    The volume would be 24, 3 L.

    Explanation:

    We apply the ideal gas law, we convert the unit of temperature in celsius to degrees Kelvin, we clear the volume of the formula and we use the constant R of the ideal gases that has a value of 0.082 l atm / K mol:

    0°C = 273 K - --> 35°C = 273 + 35 = 308K

    PV=nRT - --> V = nRT/P

    V = 1 mol x 0.082 l atm / K mol x 308 K / 1 atm = 25, 256 L
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