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20 March, 17:40

A 41.0 ml barium hydroxide solution of molarity 3.41 m is diluted with water to form 279 ml of solution. calculate the molarity of the solution

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  1. 20 March, 17:43
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    Using the dilution equation

    M1V1=M2V2

    M1 is the initial molarity, V1 the initial volume, while V2 is the final volume after dilution, while M2 is the molarity after dilution.

    Hence

    41 * 3.41 = 279 * M2

    M2 = (41 * 3.41) / 279

    = 0.5011 M

    Therefore; the molarity after dilution is 0.5011 M
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