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24 July, 03:44

N2 + 3 H2 - > 2 NH3

How many mols of N2 will be produced if it reacts with 2.5 x 1021 molecules of N2

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  1. 24 July, 04:07
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    N2 + 3H2 = 2NH3

    First, we need to determine the number of N2 moles:

    n (N2) = N/NA = 2.5 x 10²¹ / 6x10²³ = 0.0042 mole

    According to the equation of the reaction of ethane combustion, nitrogen and ammonia have following stoichiometric ratio:

    n (N2) : n (NH3) = 1 : 2

    n (NH3) = 2xn (N2)

    n (NH3) = 2x0.0042 = 0.0083 mole of NH3 will be produced in the reaction
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