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7 May, 18:14

If 27.31mL of 0.2115 M NaOH is able to nuetralize 37.45mL of HCI what is the concentration of the acid?

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  1. 7 May, 18:24
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    Taking into account that

    Normality of NaOH = N1=0.2115 N

    Volume of NaOH = V1=27.31 ml

    Normality of HCl = N2=x N

    Volume of HC l=37.45 ml

    We may proceed like this:

    V1*N1=V2*N2 27.31*0.2115=37.45*x, x=0.1542 N=0.1542 M.

    Concentration of HCl = 0.1542 moles/liter.

    Hope this is good for you
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