You have two solutions separated by a semipermeable membrane that only allows water to pass through it. The right side of the membrane has 2.0 moles of sucrose (MW 324g/mol), and the left side has 2.0 moles of fructose (MW 180g/mol). Will the solution rise on the right, rise on the left, or remain at a matching level on both sides? What reason do you have for the answer you have selected?

Question

Avah Mclaughlin

Chemistry

15 September, 22:37

You have two solutions separated by a semipermeable membrane that only allows water to pass through it. The right side of the membrane has 2.0 moles of sucrose (MW 324g/mol), and the left side has 2.0 moles of fructose (MW 180g/mol). Will the solution rise on the right, rise on the left, or remain at a matching level on both sides? What reason do you have for the answer you have selected?

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Answers (1)

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Roberto · Answer 1

The solution remain at a matching level on both sides, because they have the same molarity.

Explanation:

The osmosis is the spontaneous passage of water by a membrane, from a less concentrated solution to a higher concentration solution, to made them reach an equilibrium.

We know that the number of moles of the compound is the same in both sides of the membrane, without knowing the volume it's impossible to identify the molarity, to identify which one is more concentrated. Let's suppose that the volumes are the same.

Because of that, the molarity is the same on both sides of the membrane, so, the solutions are already in equilibrium, then the solution remains at a matching level on both sides.