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27 April, 14:17

At a constant temperature, 600 mL of an ideal gas is at a pressure of 760 mmHg. If the volume is decreased to 300 mL, the pressure of the gas will be

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  1. 27 April, 14:34
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    1520mmHg

    Explanation:

    Data obtained from the question include:

    V1 (initial volume) = 600 mL

    P1 (initial pressure) = 760 mmHg

    V2 (final volume) = 300 mL

    P2 (final pressure) =.?

    Using the Boyle's law equation P1V1 = P2V2, the final pressure of the gas can easily be obtained as shown below:

    P1V1 = P2V2

    760 x 600 = P2 x 300

    Divide both side by 300

    P2 = (760 x 600) / 300

    P2 = 1520mmHg

    The final pressure of the gas is 1520mmHg
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