Ask Question
1 May, 18:44

A chemist began with 61.5 grams of naclo3. After collecting and drying the product, 30 grams of nacl was obtained. what was the theoretical yield of nacl

+5
Answers (1)
  1. 1 May, 19:01
    0
    33.78 g

    Explanation:

    NaClO3 decomposes to NaCl and O2 by this reaction:

    2NaClO3 - -> 2NaCl + 3O2

    Let's determines the mole of chlorate we used (mass / molar mass)

    61.5 g / 106.45 g/mol = 0.578 moles.

    Ratio is 2:2, so x amount of chlorate will produce x amount of chloride. In conclussion we made 0.578 moles of NaCl from 0.578 moles of chlorate. Let's convert the moles to mass:

    0.578 mol. 58.45g/1mol = 33.78 g

    That is the theoretical yield of NaCl.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A chemist began with 61.5 grams of naclo3. After collecting and drying the product, 30 grams of nacl was obtained. what was the theoretical ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers