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26 January, 08:52

A sample of gas has a volume of 1.20 L at standard conditions. Find its volume at 35.0 oC and 900 torr. (R = 62.4 L torr/K * mol)

Group of answer choices

A. 1.14 L

B. 2.52 L

C. 0.980 mL

D. 3.92 mL

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Answers (2)
  1. 26 January, 09:13
    0
    Answer: 1.14L

    Explanation:

    P1V1/T1=P2V2/T2

    P1=760torr

    V=1.20L

    T1=373K

    P2=900torr

    V2=?

    T2=308K

    P1V1T2=P2V2T1

    V2 = P1V1T2/P2T1

    V2=760*1.20*308/900*273

    V2=280896/245700

    V2=1.14L
  2. 26 January, 09:21
    0
    Option A. 1.14L

    Explanation:

    Data obtained from the question include:

    V1 = 1.20 L

    P1 = at stp = 760torr

    T1 = at stp = 273K

    P2 = 900torr

    T2 = 35°C = 35 + 273 = 308K

    V2 = ?

    Using P1V1/T1 = P2V2/T2, we can obtain the new volume as follows:

    P1V1/T1 = P2V2/T2

    (760 x 1.2) / 273 = (900 x V2) / 308

    Cross multiply to express in linear form

    273 x 900 x V2 = 760 x 1.2 x 308

    Divide both side by 273 x 900

    V2 = (760 x 1.2 x 308) / (273 x 900)

    V2 = 1.14L
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