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12 March, 20:15

Aqueous silver ion reacts with aqueous chloride ion to yield a white precipitate of solid silver chloride. When 10.0 mL of 1.00M AgNO3 solution is added to 10.0mL of 1.00 M NaCl solution at 25oC in a calorimeter a white precipitate of AgCl forms and the temperature of the aqueous mixture increases to 32.6oC. Assuming that the specific heat of the aqueous mixture is 4.18 J/goC, that the density of the mixture is 1.00 g/mL, and that the calorimeter itself absorbs a negligible amount of heat, calculate the amount of heat absorbed in kJ/mol of Ag+.

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  1. 12 March, 20:27
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    AgNO3 + NaCl - -> AgCl + NaNO3

    Number of moles

    AgNO3

    = molar concentration * volume

    = 1 * 0.01

    = 0.01 mol

    NaCl

    = 0.01 * 1

    = 0.01 mol.

    By stoichiometry, 1 mole of silver nitrate reacted with 1 mole of NaCl. Therefore,

    Number of moles of AgCl formed = 0.01 * 1

    = 0.01 mol AgCl formed.

    Heat absorbed by solution during precipitation:

    Mass of solution = density * total volume

    = 1 * 20

    = 20 g.

    q = m * Cp * (T2 - T1)

    = 20 * 4.18 * (32.6 - 25.0)

    = 635 J

    Since 635 J was absorbed by the solution, the reaction released - 635 J

    So, Delta H = - 635 J/0.01 mol

    = - 63500 J/mol

    = - 63.5 kJ/mol.
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