Ask Question
23 September, 02:53

Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese (IV) oxide. 4HCl (aq) + MnO2 (s) ⟶MnCl2 (aq) + 2H2O (l) + Cl2 (g) A sample of 37.7 g MnO2 is added to a solution containing 46.3 g HCl. What is the limiting reactant? HCl MnO2

+1
Answers (1)
  1. 23 September, 03:07
    0
    HCl is the limiting reactant.

    Explanation:

    The reactant that yields the lesser number of moles of product is the limiting reactant

    Number of moles of MnO2 = mass of MnO2 / molar mass of MnO2

    Number of moles = 37.7g/86.9368 g/mol = 0.4336 moles

    From the reaction equation,

    If 1 mole of MnO2 yields 1 mole of chlorine gas

    0.4336 moles of MnO2 also yield 0.4336 moles of chlorine gas

    For HCl

    Number of moles of HCl = mass of HCl / molar mass of HCl

    Number of moles = 46.3g/36.46 g/mol = 1.27 moles of HCl

    If 4 moles of HCl yields 1 mole of chlorine gas

    1.27 moles of HCl will yield 1.27*1/4 = 0.3175 moles of HCl

    Hence HCl is the limiting reactant.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese (IV) oxide. 4HCl (aq) + MnO2 (s) ⟶MnCl2 ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers