What is the energy needed to raise 2.004g of water from 89.0°C to 139.0°C?

The answer to your question is E = 419.435 J

Explanation:

Data

Mass = m = 2.004 g

Temperature 1 = T1 = 89°C

Temperature 2 = T2 = 139°C

Specific heat of water = Cp = 4.186 J/g°C

Energy = E = ?

Formula

E = mCp (T2 - T1)

Substitution

E = (2.004) (4.186) (139 - 89)

Simplification and result

E = 8.3887 (50)

E = 419.435 J